Ta thấy: \(\sqrt{x^2-25}\ge0\)
\(\Rightarrow-\sqrt{x^2-25}\le0\)
\(\Rightarrow3-\sqrt{x^2-25}\le3\)
\(\Rightarrow B\le3\)
Đẳng thức xảy khi \(\sqrt{x^2-25}=0\Leftrightarrow x^2-25=0\Leftrightarrow x^2=25\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)
Vậy \(Max_B=3\) khi \(\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\)