d: Ta có: \(\left(2x-1\right)\left(3x+1\right)+\left(3x-4\right)\left(3-2x\right)=5\)
\(\Leftrightarrow6x^2+2x-3x-3+9x-6x^2-12+8x=5\)
\(\Leftrightarrow16x=5+15=20\)
hay \(x=\dfrac{5}{4}\)
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