Question

\(\frac{10}{3}-\frac{3x-1}{4\left(x+3\right)}=\frac{7x+2}{6\left(x+3\right)}\)

Answer 1

\(\frac{10}{3}-\frac{3x-1}{4\left(x+3\right)}=\frac{7x+2}{6\left(x+3\right)}\) \(\left(ĐKXĐ:x\ne-3\right)\)

\(\Leftrightarrow40\left(x+3\right)-3\left(3x-1\right)=2\left(7x+2\right)\)

\(\Leftrightarrow40x+120-9x+3=14x+4\)

\(\Leftrightarrow17x=-119\Leftrightarrow x=-7\)