Bài 2:
a: \(x^2+2>=2\)
\(\Leftrightarrow\dfrac{8}{x^2+2}< =4\)
\(\Leftrightarrow B>=-4\)
Dấu '=' xảy ra khi x=0
b: \(4+2\left(x-2\right)^2>=4\)
=>C=1/4+2(x-2)^2<=1/4
Dấu '=' xảy ra khi x=2
Bài 3:
a: \(\Leftrightarrow\dfrac{x+5-x+3}{x-3}< 0\)
=>x-3<0
=>x<3
b: \(\Leftrightarrow\dfrac{x+3-2x-8}{x+4}>0\)
\(\Leftrightarrow\dfrac{-x-5}{x+4}>0\)
=>(x+5)/(x+4)<0
=>-5<x<-4