CTPT: CnH2n+2
\(n_{C_nH_{2n+2}}=\dfrac{2,9}{14n+2}\left(mol\right)\)
Bảo toàn C: \(n.\dfrac{2,9}{14n+2}=\dfrac{20}{100}=0,2\)
=> n = 4
=> CTPT: C4H10
Phản ứng tách:
- Tách H2: \(C_4H_{10}\underrightarrow{t^o,xt}C_4H_8+H_2\)
- Cracking: \(C_4H_{10}\underrightarrow{t^o,xt}\left[{}\begin{matrix}CH_4+C_3H_6\\C_2H_4+C_2H_6\end{matrix}\right.\)