CTHH: CnH2n+2
Gọi số mol CnH2n+2 là a (mol)
\(n_{K_2CO_3}=0,1.0,3=0,03\left(mol\right)\)
=> \(n_{CO_2}=0,03\left(mol\right)\)
=> \(n_C=an=0,03\left(mol\right)\)
=> \(a=\dfrac{0,03}{n}\)
=> \(M_{C_nH_{2n+2}}=14n+2=\dfrac{0,45}{\dfrac{0,03}{n}}\left(g/mol\right)\)
=> n = 2
=> CTPT: C2H6
CTCT: \(CH_3-CH_3\)