\(\dfrac{x+2}{0,5}=\dfrac{2x+1}{2}\)
\(\Leftrightarrow\left(x+2\right).2=\left(2x+1\right).0,5\)
\(\Leftrightarrow2x+4=x+0,5\)
\(\Leftrightarrow x=-3,5\)
Vậy...
\(\dfrac{x+2}{0,5}=\dfrac{2x+1}{2}\)
\(\Leftrightarrow\dfrac{4.\left(x+2\right)}{2}=\dfrac{2x+1}{2}\)
\(\Rightarrow4x+8=2x+1\)
\(\Leftrightarrow4x-2x=1-8\)
\(\Leftrightarrow2x=-7\)
\(\Leftrightarrow x=\dfrac{-7}{2}\)
Vậy \(x=\dfrac{-7}{2}\)
\(\dfrac{x+2}{0,5}=\dfrac{2x+1}{2}\)
\(\Rightarrow\dfrac{4\left(x+2\right)}{2}=\dfrac{2x+1}{2}\)
\(\Rightarrow\dfrac{4x+8}{2}=\dfrac{2x+1}{2}\)
\(\Rightarrow4x+8=2x+1\)
\(\Rightarrow4x+2x=8+1\)
\(\Rightarrow6x=9\)
\(\Rightarrow x=\dfrac{9}{6}=\dfrac{3}{2}\)
Vậy \(x=\dfrac{3}{2}\)
