Bài 1:Thực hiện phép tính.
1) \(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\) ; 2)\(\dfrac{15^3+5\cdot15^2-5^3}{18^2+6\cdot18^2-6^3}\)
Bài 2:Tìm x, biết:
1)\(^{\left(5x+1\right)^2}\)=\(\dfrac{36}{49}\) ; 2) \(2^{x-1}=16\) ; 3)\(\left(-\dfrac{3}{4}\right)^{3x-1}=-\dfrac{27}{64}\) ; 4)\(\dfrac{-1}{2}+\dfrac{5}{x+3}=\dfrac{-5}{6}\)
5)\(\dfrac{37-x}{x+13}=\dfrac{3}{7}\) ; 6)\(\dfrac{1}{12}:\dfrac{4}{21}=3\dfrac{1}{2}:\left(3x-2\right)\) ; 7) \(^{2^{2x+1}+4^{x+3}=264}\) ; 8) \(\dfrac{x+7}{-20}=\dfrac{-5}{x+7}\)
9) \(\dfrac{x}{8}=\dfrac{x}{x^3}\) ; 10) \(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)
Mọi người giúp mình với,làm ơn !!!!!
Bài 2:
1: =>5x+1=6/7 hoặc 5x+1=-6/7
=>5x=-1/7 hoặc 5x=-13/7
=>x=-1/35 hoặc x=-13/35
2: =>x-1=4
=>x=5
3: =>3x-1=3
=>3x=4
=>x=4/3
4: \(\Leftrightarrow\dfrac{5}{x+3}=\dfrac{-5}{6}+\dfrac{1}{2}=\dfrac{-5+3}{6}=\dfrac{-2}{6}=\dfrac{-1}{3}\)
=>x+3=-15
=>x=-18
7: \(\Leftrightarrow2^{2x+1}+2^{2x+6}=264\)
=>2^2x+1*(1+2^5)=264
=>2^2x+1=8
=>2x+1=3
=>x=1
9: =>x^4=8x
=>x^4-8x=0
=>x=2
