https://loigiaihay.com/nguoi-chan-cuu-va-su-tu-c121a19561.html
\(\dfrac{3a-2b}{5}\)=\(\dfrac{2c-5a}{3}\)=\(\dfrac{5b-3c}{2}\)=\(\dfrac{15a-10b}{5}\)=\(\dfrac{6c-15a}{9}\)=\(\dfrac{10b-6c}{2}\)
Suy ra: \(\dfrac{15a-10b+6c-15a+10b-6c}{25+9+4}\)=\(\dfrac{0}{38}\)=0
Suy ra: 3a=2b\(\Leftrightarrow\)\(\dfrac{a}{2}\)=\(\dfrac{b}{3}\)(1)
2c=5a\(\Leftrightarrow\)\(\dfrac{c}{5}\)=\(\dfrac{a}{2}\)(2)
Từ (1) và (2) suy ra: \(\dfrac{a}{2}\)=\(\dfrac{b}{3}\)=\(\dfrac{c}{5}\)
Theo tính chất của dãy tỉ số bằng nhau ta được:
\(\dfrac{a}{2}\)=\(\dfrac{b}{3}\)=\(\dfrac{c}{5}\)=\(\dfrac{a+b+c}{2+3+5}\)=\(\dfrac{-50}{10}\)=-5
Tự làm nốt nha.
Đúng thì tick cho mk nha
