\(\Leftrightarrow\dfrac{3}{4\left(x-5\right)}-\dfrac{15}{2\left(x-5\right)\left(x+5\right)}+\dfrac{7}{6\left(x+5\right)}=0\)
\(\Leftrightarrow3\cdot3\left(x+5\right)-15\cdot6+7\cdot2\cdot\left(x-5\right)=0\)
=>9x+45-90+14x-70=0
=>23x-115=0
hay x=5(loại)