\(\dfrac{-6x-4}{\left(x+1\right)\left(x-1\right)}\)
\(\dfrac{-6x-4}{\left(x+1\right)\left(x-1\right)}\)
giups em voiws em caanf gaasp
c) \(\dfrac{x}{x^3+1};\dfrac{x-1}{x+1};\dfrac{x+2}{x^2-x+1}\)
d) \(\dfrac{2}{x^2+5x};\dfrac{x+5}{x^2+10+25};\dfrac{x+2}{x}\)
Quy đồng mẫu thức:
a) \(\dfrac{3x+5}{x^2-5x}+\dfrac{25-x}{25-5x}\)
b) \(\dfrac{x+1}{x+3}+\dfrac{x-7}{x^2+x-6}+\dfrac{1}{x-2}\)
bài 1; Quy đồng mẫu thức các phân thức sau:
c) \(\dfrac{x}{x^3+1};\dfrac{x-1}{x+1};\dfrac{x+2}{x^2-x+1}\)
d) \(\dfrac{2}{x^2+5x};\dfrac{x+5}{x^2+10x+25};\dfrac{x+2}{x}\)
bài 1 : rút gọn các phân thức sau
a, \(\dfrac{x^2-2x}{x^2-4}\)
b, \(\dfrac{x^2+5x+4}{x^2-1}\)
c,\(\dfrac{x^4+4}{x\left(x^2+2\right)-2x^2-\left(x-1\right)^2-1}\)
bài 2 : rút gọn các biểu thức sau.
a,\(\left(\right)\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\left(\right):\dfrac{4x}{10x-5}\)
b, \(\left(\dfrac{1}{x^2+x}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+x-2\right)\)
c, \(\left(\dfrac{5x+2}{x^2-10x}\dfrac{5x-2}{x^2+10x}\right)\times\dfrac{x^2-100}{x^2+4}\)
Quy đồng mẫu thức các phân thức :
a) \(\dfrac{7x-1}{2x^2+6x};\dfrac{5-3x}{x^2-9}\)
b) \(\dfrac{x+1}{x-x^2};\dfrac{x+2}{2-4x+2x^2}\)
c) \(\dfrac{4x^2-3x+5}{x^3-1};\dfrac{2x}{x^2+x+1};\dfrac{6}{x-1}\)
d) \(\dfrac{7}{5x};\dfrac{4}{x-2y};\dfrac{x-y}{8y^2-2x^2}\)
e) \(\dfrac{5x^2}{x^3+6x^2+12x+8};\dfrac{4x}{x^2+4x+4};\dfrac{3}{2x+4}\)
a) \(\dfrac{2x-1}{x+1}\) và \(\dfrac{-4x}{5+5x}\)
b) \(\dfrac{-7}{3x-2}\) và \(\dfrac{1+x}{6x+4}\)
Quy đồng mẫu thức các phân thức sau:
a) \(\dfrac{3x-6}{x^2-4x+4};\dfrac{5x-5}{2x^2-2}\)
b) 2;\(\dfrac{2a+1}{a^3-1};\dfrac{-a}{1-a}\)
c) \(\dfrac{x+1}{x^2-6x+5};\dfrac{2x}{x^3-6x^2+11x-6};\dfrac{1}{x^2-3x+2}\)
\(\dfrac{1}{3x-3y};\dfrac{1}{x^2-2xy+y^{ }2}\)
\(\dfrac{3}{x^2-3x};\dfrac{5}{2x-6}\)
\(\dfrac{x}{x+3};\dfrac{1}{3-x};\dfrac{1}{x^2-9}\)
\(\dfrac{1}{x^2+xy};\dfrac{1}{xy-ỳ^2};\dfrac{2}{y^2-x^2}\)
giúp với ạ :((
\(\dfrac{2}{36a^2b^2-1};\dfrac{1}{6ab+1^2};\dfrac{1}{6ab-1^2}\)
\(\dfrac{x}{x^3-27};\dfrac{2x}{x^2-6x+9};\dfrac{1}{x^2+3x+9x}\)
\(\dfrac{x^2-x}{x^2-1};\dfrac{3x}{x^3+2x^2+x};2x\)
giúp với ạ