\(\Leftrightarrow\left(\dfrac{1}{3}\right)^x\cdot\dfrac{28}{27}=\dfrac{28}{243}\)
hay x=2
Đúng 1
Bình luận (1)
Đại số lớp 7
Các câu hỏi tương tự
\((\dfrac{1}{3})^x+(\dfrac{1}{3})^{x+3}=\dfrac{28}{243}\)
Tìm x biết:
a) dfrac{-32}{left(-2right)^x}4 f) left(3x-1right)^3dfrac{-8}{27}
b) left(dfrac{1}{2}right)^{2x-1}dfrac{1}{8} g) left(2x+3right)^2dfrac{9}{121}
c) dfrac{1}{9}.27^x3^x h) 5^x+5^{x+2}650
d) 9^x:3^3dfrac{1}{243} i) left(x-7right)^{x+1}-left(x-7right)0
e) dfrac{x7}{81}27...
Đọc tiếp
Tìm x biết:
a) \(\dfrac{-32}{\left(-2\right)^x}=4\) f) \(\left(3x-1\right)^3=\dfrac{-8}{27}\)
b) \(\left(\dfrac{1}{2}\right)^{2x-1}=\dfrac{1}{8}\) g) \(\left(2x+3\right)^2=\dfrac{9}{121}\)
c) \(\dfrac{1}{9}.27^x=3^x\) h) \(5^x+5^{x+2}=650\)
d) \(9^x:3^3=\dfrac{1}{243}\) i) \(\left(x-7\right)^{x+1}-\left(x-7\right)=0\)
e) \(\dfrac{x7}{81}=27\) m) \(\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
dfrac{x+4}{2000}+dfrac{x+3}{2001}dfrac{x+2}{2002}+dfrac{x+1}{2003}
1/* Chứng minh rằng:
dfrac{1}{1times2}+dfrac{1}{3times4}+dfrac{1}{5times6}+...dfrac{1}{49times50}dfrac{1}{26}+dfrac{1}{27}+dfrac{1}{28}+..+dfrac{1}{50}
2/* Cho:
Adfrac{1}{1times2}+dfrac{1}{3times4}+dfrac{1}{5times6}+.....+dfrac{1}{99times100}. Chứng minh rằng:dfrac{7}{12} Adfrac{5}{6}
Các bn giúp mk những bài này nha!
Đọc tiếp
\(\dfrac{x+4}{2000}+\dfrac{x+3}{2001}=\dfrac{x+2}{2002}+\dfrac{x+1}{2003}\)
1/* Chứng minh rằng:
\(\dfrac{1}{1\times2}+\dfrac{1}{3\times4}+\dfrac{1}{5\times6}+...\dfrac{1}{49\times50}=\dfrac{1}{26}+\dfrac{1}{27}+\dfrac{1}{28}+..+\dfrac{1}{50}\)
2/* Cho:
A=\(\dfrac{1}{1\times2}+\dfrac{1}{3\times4}+\dfrac{1}{5\times6}+.....+\dfrac{1}{99\times100}\). Chứng minh rằng:\(\dfrac{7}{12}< A>\dfrac{5}{6}\)
Các bn giúp mk những bài này nha!
Tìm x biết
1, \(\dfrac{-1}{4}-\dfrac{3}{4}:x=-\dfrac{11}{36}\)
2,\(\dfrac{3}{4}x-\dfrac{1}{2}=\dfrac{3}{7}\)
Tìm x bik : a. \(0,5.\left(x-\dfrac{1}{3}\right)-\dfrac{1}{2}=x+\dfrac{-4}{5}\) b. \(\dfrac{2}{3}.\left(\dfrac{1}{2}.x-\dfrac{1}{3}\right)+\dfrac{1}{2}=\dfrac{2}{3}-x\)
5. \(3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|\) 6. \(3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=x-\dfrac{1}{2}\) 7. \(\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-x\)
5. \(3-1\dfrac{1}{2}-x+\dfrac{5}{4}=2-\left|1\dfrac{1}{8}-\dfrac{5}{12}\right|\) 6. \(3\dfrac{1}{14}-5\dfrac{1}{3}-\dfrac{4}{7}+\dfrac{11}{21}=-\dfrac{1}{2}\) 7. \(\dfrac{11}{-40}+\dfrac{4}{5}-\left|\dfrac{3}{4}-1\dfrac{5}{12}\right|=\dfrac{3}{20}-X\)
1) tìm x:
\(\left(\dfrac{1}{7}x-\dfrac{2}{7}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)=0\)
\(\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}=\dfrac{x+1}{13}+\dfrac{x+1}{14}\)
\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
Mn giúp mk làm bài này nhoa !!!