\(\Leftrightarrow cosx=cos\left(\pi-x-\frac{\pi}{3}\right)\)
\(\Leftrightarrow cosx=cos\left(\frac{2\pi}{3}-x\right)\)
\(\Leftrightarrow x=\frac{2\pi}{3}-x+k2\pi\)
\(\Leftrightarrow x=\frac{\pi}{3}+k2\pi\)
\(\Leftrightarrow cosx=cos\left(\pi-x-\frac{\pi}{3}\right)\)
\(\Leftrightarrow cosx=cos\left(\frac{2\pi}{3}-x\right)\)
\(\Leftrightarrow x=\frac{2\pi}{3}-x+k2\pi\)
\(\Leftrightarrow x=\frac{\pi}{3}+k2\pi\)
giải các pt
a) \(sin\left(\frac{3\pi}{10}-\frac{x}{2}\right)=\frac{1}{2}sin\left(\frac{\pi}{10}+\frac{3x}{2}\right)\)
b) \(4\left(sin^2x+\frac{1}{sin^2x}\right)+4\left(sinx+\frac{1}{sinx}\right)=7\)
c) \(9\left(\frac{2}{cosx}+cosx\right)+2\left(cos^2x+\frac{4}{cos^2x}\right)=1\)
d) \(2\left(cos^2x+\frac{4}{cos^2x}\right)+9\left(\frac{2}{cosx}-cosx\right)=1\)
Tìm GTLN, GTNN
\(y=cosx+cos\left(x-\frac{\pi}{3}\right)\)
Giải phương trình:
a) \(sin\left(\frac{\pi}{6}cosx+\frac{\pi}{3}\right)=0\)
b) \(cos\left(\pi cos3x\right)=0\)
c) \(tan\left(\frac{\pi}{3}sin\pi x\right)=\frac{1}{\sqrt{3}}\)
Xét tính chẵn, lẻ của các hàm số
1,\(y=cosx+sin^2x\)
2,\(y=sinx+cosx\)
3,\(y=tanx+2sinx\)
4,\(y=tan2x-sin3x\)
5,\(sin2x+cosx\)
6,\(y=cosx.sin^2x-tan^2x\)
7,\(y=cos\left(x-\dfrac{\pi}{4}\right)+cos\left(x+\dfrac{\pi}{4}\right)\)
8,\(y=\dfrac{2+cosx}{1+sin^2x}\)
9,\(y=\left|2+sinx\right|+\left|2-sinx\right|\)
tìm GTLN,GTNN của hàm số sau:
a, \(y=\frac{1}{sinx}+\frac{1}{cosx},x\in\left(0,\frac{\pi}{2}\right)\)
b, \(y=\frac{1}{1-cosx}+\frac{1}{1+cosx},x\in\left(0,\frac{\pi}{2}\right)\)
c, \(y=2+tan^2x+cot^2x+\frac{1}{sin^4x+cos^4x},x\in\left(0,\frac{\pi}{2}\right)\)
giải các pt
a) \(sin^3x.cosx-sinx.cos^3x=\frac{\sqrt{2}}{8}\)
b) \(sin^3x-cos^24x=sin^25x-cos^26x\)
c) \(\left(2sinx-cosx+1\right)\left(1+cosx\right)=sin^2x\)
d) \(sin7x+sin9x=2\left[cos^2\left(\frac{\pi}{4}-x\right)-cos^2\left(\frac{\pi}{4}+2x\right)\right]\)
Giải các pt sau
a, \(\dfrac{1}{sinx}+\dfrac{1}{cosx}=4sin\left(x+\dfrac{\pi}{4}\right)\)
b, \(2sin\left(2x-\dfrac{\pi}{6}\right)+4sinx+1=0\)
c, \(cos2x+\sqrt{3}sinx+\sqrt{3}sin2x-cosx=2\)
d, \(4sin^2\dfrac{x}{2}-\sqrt{3}cos2x=1+cos^2\left(x-\dfrac{3\pi}{4}\right)\)
giai cac pt
a) \(sin^3\left(x+\frac{\pi}{4}\right)=\sqrt{2}sinx\)
b) \(cos^3x-sin^3x=\sqrt{2}cos\left(x-\frac{\pi}{4}\right)\)
c) \(\frac{1-tanx}{1+tanx}=1+2sinx\)
d) \(\left(1+tanx\right)sin^2x=3sinx\left(cosx-sinx\right)+3\)
Phương trình : \(\sqrt{3}sinx-cosx=1\) tương đương với phương trình nào sau đây ?
A. \(sin\left(\frac{\Pi}{6}-x\right)=1\)
B. \(sin\left(\frac{\Pi}{6}-x\right)=\frac{1}{2}\)
C. \(sin\left(x-\frac{\Pi}{6}\right)=\frac{1}{2}\)
D. \(cos\left(x+\frac{\Pi}{3}\right)=\frac{1}{2}\)