\(8^{30}+8^{31}+8^{32}\)
\(=8^{30}.1+8^{30}.8+8^{30}.8^2\)
\(=8^{30}.1+8^{30}.8+8^{30}.64\)
\(=8^{30}\left(1+8+64\right)\)
\(=8^{30}.73\)
\(=\left(2^3\right)^{30}.73\)
\(=2^{90}.73\)
\(=2^{89}.146⋮146\rightarrowđpcm\)
\(4^{25}+4^{26}+4^{27}+4^{28}+4^{29}+4^{30}\)
\(=4^{25}.1+4^{25}.4+4^{25}.4^2+4^{25}.4^3+4^{25}.4^4+4^{25}.4^5\)
\(=4^{25}.1+4^{25}.4+4^{25}.16+4^{25}.64+4^{25}.256+4^{25}.1024\)
\(=4^{25}\left(1+4+16+64+256+1024\right)\)
\(=4^{25}.1365\)
\(=4^{25}.195.7⋮7\rightarrowđpcm\)
à há, giờ mới biết mi làm sao biết đc cách giải BTVN 
1.
a) Ta có :
\(8^{30}+8^{31}+8^{32}=8^{30}\left(8+8^2+8^3\right)\)
\(=8^{30}.584\)
* Do \(584⋮146\Rightarrow584.8^{30}⋮146\)
Vậy \(8^{30}+8^{31}+8^{32}⋮146\)
b) \(4^{25}+4^{26}+4^{27}+4^{28}+4^{29}+4^{30}\)
\(=\left(4^{25}+4^{26}\right)+\left(4^{27}+4^{28}\right)+\left(4^{29}+4^{30}\right)\)\(=4^{25}\left(1+4^2\right)+4^{27}\left(1+4^2\right)+4^{29}\left(1+4^2\right)\)\(=\left(1+4^2\right)\left(4^{25}+4^{27}+4^{29}\right)\)
\(=17\left(4^{25}+4^{27}+4^{29}\right)⋮17\)
\(\RightarrowĐpcm\)
tik mik nha !!!
học ngu như con bò suốt ngày lên học 24
