Question

cho

x^2 +y^2=1

(x⁴:2) +(y⁴:b)=1:(a+b)

CMR (x²⁰¹⁸ :a²⁰¹⁸)+(y²⁰¹⁸:b²⁰¹⁸)=1

Answer 1

Ad C-S

\(\dfrac{x^4}{a}+\dfrac{y^4}{b}=\dfrac{\left(x^2\right)^2}{a}+\dfrac{\left(x^2\right)^2}{b}\ge\dfrac{\left(x^2+y^2\right)^2}{a+b}=\dfrac{1}{a+b}\)