\(\frac{cosa+sina}{cosa-sina}=\frac{\frac{cosa}{cosa}+\frac{sina}{cosa}}{\frac{cosa}{cosa}-\frac{sina}{cosa}}=\frac{1+tana}{1-tana}=\frac{1+3}{1-3}=-2\)
\(\frac{cosa+sina}{cosa-sina}=\frac{\frac{cosa}{cosa}+\frac{sina}{cosa}}{\frac{cosa}{cosa}-\frac{sina}{cosa}}=\frac{1+tana}{1-tana}=\frac{1+3}{1-3}=-2\)
Cho \(\tan\alpha=\frac{3}{5}\), hãy tính giá trị của:
a) \(M=\frac{\sin\alpha+\cos\alpha}{\sin\alpha-\cos\alpha}\)
b) \(N=\frac{\sin\alpha\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)
c) \(P=\frac{\sin^3\alpha+\cos^3\alpha}{2\sin\alpha\cos^2\alpha+\cos\alpha\sin^2\alpha}\)
CMR
a)\(\frac{1+\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{1-\cos\alpha}\)
b)\(\frac{\tan\alpha+1}{\tan\alpha-1}=\frac{1+\cot\alpha}{1-\cot\alpha}\)
c) \(\tan^2\alpha-\sin^2\alpha=\tan^2\alpha.\sin^2\alpha\)
d)\(\frac{1-4\sin^2\alpha.\cos^2\alpha}{\left(\sin\alpha-\cos\alpha\right)^2}=\left(\sin\alpha+\cos\alpha\right)^2\)
a, Cho cos α = 0,8. Hãy tính: sin α, tan α, cot α ?
b, Hãy tìm sin α, cos α, biết tan α = \(\frac{1}{3}\)
Tính E=\(\frac{8\cos^3\alpha-2\sin^3\alpha+\cos\alpha}{2cos\alpha-sin^3\alpha}\) khi tan α=2, góc α nhọn
Hãy đơn giản các biểu thức:
a) 1-sin2α
b) (1-cosα)(1+cosα)
c) 1+cos2α+sin2α
d) sinα-sinα cos2α
e) sin4α+cos4α+2sin2α cos2α
f) tan2α-sin2α tan2α
g) cos2α+tan2α cos2α
h) tan2α (2cos2α+sin2α-1)
Chứng minh:
a)\(cot^2\alpha-cos^2\alpha\cdot cot^2\alpha=cos^2\alpha\)
b)\(tan^2\alpha-sin^2\alpha\cdot tan^2\alpha=sin^2\alpha\)
c) \(\dfrac{1-cos^2}{sin\alpha}\) = \(\dfrac{sin\alpha}{1+cos\alpha}\)
d)\(tan^2\alpha-sin^2\alpha=tan^2\cdot sin^2\alpha\)
e) \(\sin^6\alpha+cos^6\alpha+3sin^2\cdot cos^2\alpha=1\)
CM các hệ thức sau:
a) \(1+\tan^2\alpha=\frac{1}{\cos^2\alpha}\)
b) \(1+\cot^2\alpha=\frac{1}{\sin^2\alpha}\)
c) \(\cot^2\alpha-\cos^2\alpha=\cot^2\alpha.\cos^2\alpha\)
d) \(\frac{1+\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{1-\cos\alpha}\)
1. Chứng minh rằng: \(\frac{1-2\sin.\cos\alpha}{sin^2\alpha-\cos^2\alpha}=\frac{sin\alpha-\cos\alpha}{sin\alpha+\cos\alpha}\) (\(\alpha\ne45^o\))
2. Chứng minh: \(\cos^4\alpha+\sin^2\alpha.\cos^2\alpha+\sin^2\alpha\) không phụ thuộc vào x
Biết tan\(\alpha=3.\) Tính M =\(\frac{\sin\alpha.\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)