Xét \(\Delta AMB\&\Delta DCB\) ( đều vuông,\(\widehat{ABM}=\widehat{DBC}\)) suy ra \(\widehat{AMB}=\widehat{DCB}\)
Mà \(\widehat{AMB}=\widehat{DMC}\Rightarrow\widehat{DCB}=\widehat{DMC}\)
Xét tgiac vuông DMC và DCB có \(\widehat{DCB}=\widehat{DMC}\)
\(\Rightarrow\Delta DMC\sim\Delta DCB\left(g-g\right)\)\(\Rightarrow\frac{DM}{DC}=\frac{DC}{DB}\Rightarrow DC^2=DM.DB\left(1\right)\)
Cần CM DA=DC..xíu CM típ