Tự Vẽ hình nhé !!!
\(\widehat{BOC}=180^0-\widehat{OBC}-\widehat{OCB}\\ =180^0-\dfrac{1}{2}\widehat{B}-\dfrac{1}{2}\widehat{C}\\ =180^0-\dfrac{1}{2}\left(\widehat{B}+\widehat{C}\right)\\ =180^0-\dfrac{1}{2}\left(180^0-\widehat{A}\right)\\ =180^0-90^0+\dfrac{1}{2}\widehat{A}\\ =90^0+\dfrac{\widehat{BAC}}{2}\)