\(\overrightarrow{BM}=\frac{1}{2}\left(\overrightarrow{BA}+\overrightarrow{BD}\right)=\frac{1}{2}\overrightarrow{BA}+\frac{1}{4}\overrightarrow{BC}=\frac{1}{4}\left(2\overrightarrow{BA}+\overrightarrow{BC}\right)\left(1\right)\)
\(\overrightarrow{BN}=\overrightarrow{AN}-\overrightarrow{AB}=\frac{1}{3}\overrightarrow{AC}-\overrightarrow{AB}\)
\(=\frac{1}{3}\left(\overrightarrow{BC}-\overrightarrow{BA}\right)+\overrightarrow{BA}=\frac{1}{3}\left(2\overrightarrow{BA}+\overrightarrow{BC}\right)\left(2\right)\)
Từ \(\left(1\right);\left(2\right)\Rightarrow\text{}\overrightarrow{BM}=\frac{4}{3}\text{}\overrightarrow{BN}\) hay \(B;M;N\) thẳng hàng