Hình tự vẽ
Ta có: \(AC^2=AD^2+DC^2\left(Định-lí-pitago\right)\)
\(\Rightarrow DC=\sqrt{AC^2-AD^2}=\sqrt{29^2-20^2}\)
\(\Rightarrow DC=21cm\)
Ta lại có: \(AB^2=AD^2+BD^2\left(Định-li-pitago\right)\)
\(\Rightarrow AB=\sqrt{AD^2+BD^2}=\sqrt{20^2+15^2}\)
\(\Rightarrow AB=25cm\)