Xét tam giác ABC, ta có:
\(\widehat{A}+\widehat{B}+\widehat{C}=180^0\)
\(\Rightarrow20^0+\widehat{B}+\widehat{C}=180^0\)
\(\Rightarrow\widehat{B}+\widehat{C}=180^0-20^0=160^0\)
Mà \(\widehat{B}=\widehat{C}\) ( Do tam giác ABC cân )
\(\Rightarrow\widehat{B}=\widehat{C}=\dfrac{160^0}{2}=80^0\)
Vì AD = BC (gt)
=> Tam giác BCD cân
\(\Rightarrow\widehat{B}=\widehat{BDC}=80^0\)