c) Ta có:
\(\left\{{}\begin{matrix}AE+BE=AB\\AF+CF=AC\end{matrix}\right.\)
Mà \(\left\{{}\begin{matrix}AE=AF\left(gt\right)\\AB=AC\left(cmt\right)\end{matrix}\right.\)
=> \(BE=CF.\)
=> \(BE+EP=CF+EP.\)
Hay \(BE+EP=PE+FC\left(đpcm\right).\)
Chúc bạn học tốt!