a) m=0 và n=1/4
pt \(\Leftrightarrow0\left(x^2-3x+1\right)+\dfrac{1}{4}\left(x^2-3x\right)-1=0\)
\(\Leftrightarrow0+\dfrac{1}{4}\left(x^2-3x\right)-1=0\)
\(\Leftrightarrow x^2-3x-4=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)
b) m=1 và n=0
pt\(\Leftrightarrow1\left(x^2-3x+1\right)+0\left(x^2-3x\right)-1=0\)
\(\Leftrightarrow x^2-3x=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
c) m=1 và n=5
pt\(\Leftrightarrow1\left(x^2-3x+1\right)+5\left(x^2-3x\right)-1=0\)
\(\Leftrightarrow x^2-3x+1+5x^2-15x-1=0\)
\(\Leftrightarrow6x^2-18x=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
