Để pt có 2 nghiệm pb
\(\Leftrightarrow\left\{{}\begin{matrix}m+1\ne0\\\Delta=\left(2m+3\right)^2-8\left(m+1\right)>0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m\ne-1\\4m^2+4m+1>0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}m\ne-1\\m\ne-\frac{1}{2}\end{matrix}\right.\)