Gọi 2a là mol Al; a là mol Fe
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(\rightarrow n_{H2}=3a+a=4a\left(mol\right)\)
m tăng= m kim loại- mH2
\(\rightarrow27.2a+56a-2.4a=10,2\)
\(\Leftrightarrow a=0,1\)
\(\rightarrow m=m_{Al}+m_{Fe}=11\left(g\right)\)