Kẻ Oz // n
=> \(\widehat{F}=\widehat{FOz}\) (soletrong) = 300
Ta có: \(\widehat{FOz}+\widehat{EOz}=\widehat{FOE}\)
=> \(30^0+\widehat{EOz}=100^0\)
=> \(\widehat{EOz}=100^0-30^0\)
=> \(\widehat{EOz}=70^0\)
Vì \(\widehat{EOz}=\widehat{E}=70^0\)
=> Oz // m (soletrong)
mà Oz // n
=> m // n