Question

cho hàm số y=f(x) =x^2+1 tính f0,f(-1),f3,f(-3),f(½),f(-½),f(⅔),f(-⅔)

Answer 1

\(f\left(-3\right)=\left(-3\right)^2+1=9+1=10\)

\(f\left(-1\right)=\left(-1\right)^2+1=1+1=2\)

\(f\left(3\right)=3^2+1=9+1=10\)

\(f\left(0\right)=0^2+1=1\)

 

Answer 2

\(f\left(-\dfrac{1}{2}\right)=\left(-\dfrac{1}{2}\right)^2+1=\dfrac{1}{4}+\dfrac{4}{4}=\dfrac{5}{4}\)

\(f\left(\dfrac{1}{2}\right)=\left(\dfrac{1}{2}\right)^2+1=\dfrac{1}{4}+\dfrac{4}{4}=\dfrac{5}{4}\)

\(f\left(\dfrac{2}{3}\right)=\left(\dfrac{2}{3}\right)^2+1=\dfrac{4}{9}+\dfrac{9}{9}=\dfrac{13}{9}\)

\(f\left(-\dfrac{2}{3}\right)=\left(-\dfrac{2}{3}\right)^2+1=\dfrac{4}{9}+\dfrac{9}{9}=\dfrac{13}{9}\)