a, Ta có:
\(f\left(-1\right)=2.\left(-1\right)+1=-2+1=-1\)
\(g\left(-1\right)=1-2.\left(-1\right)=1+2=3\)
b, Ta có:
\(f\left[g\left(x\right)\right]=2.\left(1-2x\right)+1=2-4x+1=-4x+3\)
\(g\left[f\left(x\right)\right]=1-2.\left(2x+1\right)=1-4x-2=-\left(4x+1\right)\)
c, Để \(f\left(x\right)=g\left(x\right)\) thì \(2x+1=1-2x\)
\(\Rightarrow4x=0\Rightarrow x=0\)
Vậy x=0 thì \(f\left(x\right)=g\left(x\right)\)
Chúc bạn học tốt!!!