a) f(x) = x\(^3\) - 2x\(^2\) + x + 1
- g(x) = x\(^3\) + 0x\(^2\) + x + 1
hay f(x) = x\(^3\) - 2x\(^2\) + x + 1
+ [-g(x)] = - x\(^3\) - 0x\(^2\) - x - 1
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f(x) - g(x) = - 2x\(^2\)
f(x) - g(x) = -2x\(^2\) + 0
+ h(x) = 2x\(^2\) - 1
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f(x) - g(x) + h(x) = - 1
*Mk nqhĩ là z! Mk sợ làm hànq dọc cả 3 sẽ hay sai!