Ta có : \(\dfrac{a}{3}=\dfrac{3}{b}=\dfrac{b}{a}\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có
\(\dfrac{a}{3}=\dfrac{3}{b}=\dfrac{b}{a}=\dfrac{a+3+b}{3+b+a}=\dfrac{3+b+a}{3+a+b}=1\)
Suy ra \(\dfrac{b}{a}=1\Leftrightarrow b=a\)
Vậy a=b (đpcm)
Bài 17: Cho a, b, c là 3 số thực khác 0, thỏa mãn điều kiện : \(a+b\ne-c\) và \(\dfrac{a+b-c}{c}\)=\(\dfrac{b+c-a}{a}\)=\(\dfrac{c+a-b}{b}\). Tính giá trị biểu thức P=\(\left(1+\dfrac{b}{a}\right)\)x\(\left(1+\dfrac{a}{c}\right)\)x\(\left(1+\dfrac{c}{b}\right)\)
1 cho \(\dfrac{1}{c}=\dfrac{1}{2}\left(\dfrac{1}{a}+\dfrac{1}{b}\right)\)(với a,b,c\(\ne\)0;b\(\ne\)c CMR\(\dfrac{a}{b}=\dfrac{a-c}{c-b}\)
2 cho số tự nhiên n,chứng tỏ A=\(9^{n+2}+3^{n+2}-9^n+3^n\) chia hết cho 10
Câu 1:
a, Tính M =\(3\dfrac{1}{417}\cdot\dfrac{1}{762}-\dfrac{1}{139}\cdot4\dfrac{761}{762}-\dfrac{4}{417\cdot762}+\dfrac{5}{139}\)
b, Tính \(\left(\dfrac{3}{4}-81\right)\left(\dfrac{3^2}{5}-81\right)\left(\dfrac{3^3}{6}-81\right)...\left(\dfrac{3^{2000}}{2003}-81\right)\)
Câu 2: Cho \(\left(a+3\right)\left(b-4\right)-\left(a-3\right)\left(b+4\right)=0\) . Chứng minh \(\dfrac{a}{3}=\dfrac{b}{4}\).
Cho a, b, c ≠ 0 thỏa mãn a + b + c = 0. Tính A = \(\left(1+\dfrac{a}{b}\right)\left(1+\dfrac{b}{c}\right)\left(1+\dfrac{c}{a}\right)\)
Cho \(b^2=ac;c^2=bd\). VỚi b, c, d \(\ne\)0. b+c \(\ne\)d; \(b^3+c^3\ne d^3\)
CMR \(\dfrac{a^3+b^3-c^3}{b^3+c^3-d^3}=\left(\dfrac{a+b-c}{b+c-d}\right)^3\)
Bài 1. a, Cho A = \(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right).....\left(\dfrac{1}{10}-1\right)\)
So sánh A với \(\dfrac{-1}{9}\)
Bài 2. Cho A = \(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)....\left(\dfrac{1}{2008}-1\right)\left(\dfrac{1}{2009}-1\right)\)
B = \(\left(-1\dfrac{1}{2}\right)\left(-1\dfrac{1}{3}\right)....\left(-1\dfrac{1}{2007}\right)\left(-1\dfrac{1}{2008}\right)\)
Tính A . B ?
câu 11:
\(Cho:\dfrac{1}{c}=\dfrac{1}{2}\left(\dfrac{1}{a}+\dfrac{1}{b}\right)\left(vớia,b,c\ne0;b\ne c\right)\)
\(CMR:\dfrac{a}{b}=\dfrac{a-c}{c-b}\)
Cho a,b,c \(\ne\) 0 và \(\dfrac{a+b-c}{c}=\dfrac{a-b+c}{b}=\dfrac{-a+b+c}{a}\)
Tính M =\(\dfrac{\left(a+b\right).\left(b+c\right).\left(c+a\right)}{a.b.c}\)
\(Cho\dfrac{a}{3}=\dfrac{c}{4}=\dfrac{b}{5},CMR:4\left(a-b\right)\left(b-c\right)=\left(a-c\right)^2\)
