\(\Leftrightarrow\left(a+b\right)\left(ab+abc\right)\ge4ab\)
\(\Leftrightarrow\left(a+b\right)\left(c+1\right)\ge4\)(1)
Lại có:\(\left(a+b\right)^2\ge4ab\)
\(\left(c+1\right)^2\ge4c\)
\(\Rightarrow\left[\left(a+b\right)\left(c+1\right)\right]^2\ge16abc=16\)
\(\Rightarrow\left(a+b\right)\left(c+1\right)\ge4\)
\(\Rightarrow\left(1\right)\) đúng\(\Rightarrowđpcm\)