a: \(P=\dfrac{x^2+x+3x-3-6x+4}{\left(x-1\right)\left(x+1\right)}=\dfrac{x^2-2x+1}{\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{x+1}\)
b: Khi x=5thì \(P=\dfrac{5-1}{5+1}=\dfrac{4}{6}=\dfrac{2}{3}\)
c: Để P=4/5 thì \(\dfrac{x-1}{x+1}=\dfrac{4}{5}\)
=>5x-5=4x+4
=>x=9