Đk \(x\ge0\) và \(x\ne\pm4\)
\(M=\frac{x+2\sqrt{2}+x-2\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}.\frac{x-4}{\sqrt{4x}}=\frac{2x\left(x-4\right)}{2\sqrt{2}\left(x-4\right)}=\frac{\sqrt{2}x}{2}\)
c) Để \(M>3\Leftrightarrow\frac{\sqrt{2}x}{2}>3\Leftrightarrow\frac{\sqrt{2}x-6}{2}>0\Leftrightarrow\sqrt{2}x>6\Leftrightarrow x>\frac{6}{\sqrt{2}}\)