a: \(A=\dfrac{4y-8\sqrt{y}-8y}{y-4}:\dfrac{\sqrt{y}-1-2\sqrt{y}+4}{\sqrt{y}\left(\sqrt{y}-2\right)}\)
\(=\dfrac{-4\sqrt{y}\left(\sqrt{y}+2\right)}{y-4}\cdot\dfrac{\sqrt{y}\left(\sqrt{y}-2\right)}{-\sqrt{y}+3}\)
\(=\dfrac{4y}{\sqrt{y}-3}\)
b: Để A=-2 thì \(4y=-2\sqrt{y}+6\)
=>\(4y+2\sqrt{y}-6=0\)
=>y=1