a: \(A=\dfrac{2x+1-x-\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}:\dfrac{x+\sqrt{x}+1-x-4}{x+\sqrt{x}+1}\)
\(=\dfrac{x-\sqrt{x}}{\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)}\cdot\dfrac{x+\sqrt{x}+1}{\sqrt{x}-3}=\dfrac{\sqrt{x}}{\sqrt{x}-3}\)
b; A nguyên dương khi \(\sqrt{x}-3+3⋮\sqrt{x}-3\) và x>9
=>\(\sqrt{x}-3\in\left\{1;3\right\}\)
=>x=16 hoặc x=36