Ta có: \(\dfrac{a-1}{c}+\dfrac{c-1}{b}+\dfrac{b-1}{a}\)
= \(\dfrac{a-abc}{c}+\dfrac{c-abc}{b}+\dfrac{b-abc}{a}\)
= \(\dfrac{a(1-bc)}{c}+\dfrac{c(1-ab)}{b}+\dfrac{b(1-ac)}{a}\)
= \(\dfrac{a}{c}+\dfrac{c}{b}+\dfrac{b}{a}+\dfrac{1-bc}{c}+\dfrac{1-ab}{b}+\dfrac{1-ac}{a}\)