\(a+b+c\ge3\sqrt[3]{abc}+\left(\sqrt{a}-\sqrt{b}\right)^2\)
\(\Leftrightarrow c+2\sqrt{ab}\ge3\sqrt[3]{abc}\)
Mà ta có:
\(c+2\sqrt{ab}=c+\sqrt{ab}+\sqrt{ab}\ge3\sqrt[3]{abc}\left(ĐPCM\right)\)
Cho \(a,b,c>0\). CMR:
\(\sqrt{\dfrac{a^3}{5a^2+\left(b+c\right)^2}}+\sqrt{\dfrac{b^3}{5b^2+\left(c+a\right)^2}}+\sqrt{\dfrac{c^3}{5c^2+\left(a+b\right)^2}}\le\sqrt{\dfrac{a+b+c}{3}}\)
CMR
\(2\left(\sqrt{a}-\sqrt{b}\right)< \dfrac{1}{\sqrt{b}}< 2\left(\sqrt{b}-\sqrt{c}\right)\)
biết a,b,c là 3 số thực thoả mãn điều kiện a=b+1=c+2 và c>0
Rút gọn:
\(a,\sqrt{64a^2}+2a\left(a\ge0\right)\\ b,3\sqrt{9a^6}-6a^3\left(a\in R\right)\\ c,\sqrt{a^2+6a+9}+\sqrt{a^2-6a+9}\left(a\ge3\right)\)
Cho tam giác \(ABC\) nhọn. CMR:
\(\cos\left(\dfrac{A-B}{2}\right)+\cos\left(\dfrac{B-C}{2}\right)+\cos\left(\dfrac{C-A}{2}\right)\)
\(\le\dfrac{\sqrt{2}}{2}\left(\dfrac{a+b}{\sqrt{a^2+b^2}}+\dfrac{b+c}{\sqrt{b^2+c^2}}+\dfrac{c+a}{\sqrt{c^2+a^2}}\right)\)
Cho a, b, c > 0. CMR :
\(\dfrac{\sqrt{a^2+b^2}}{c}+\dfrac{\sqrt{b^2+c^2}}{a}+\dfrac{\sqrt{a^2+c^2}}{b}\ge2\left(\dfrac{a}{\sqrt{b^2+c^2}}+\dfrac{b}{\sqrt{a^2+c^2}}+\dfrac{c}{\sqrt{a^2+b^2}}\right)\)
1 . Cho 3 số thực dương a,b,c. CMR::
\(\sqrt{\frac{a^3}{b^3}}+\sqrt{\frac{b^3}{c^3}}+\sqrt{\frac{c^3}{a^3}}\ge\frac{a}{b}+\frac{b}{c}+\frac{c}{a}\)
2 . cho a, b, c là 3 số đôi một khác nhau thỏa mãn :
\(\frac{a}{b-c}+\frac{b}{c-a}+\frac{c}{a-b}=0\)
CMR : \(\frac{a}{\left(b-c\right)^2}+\frac{b}{\left(c-a\right)^2}+\frac{c}{\left(a-b\right)^2}=0\)
Cho x,y,z,a,b,c là các số dương. Cmr:
\(\sqrt[3]{abc}+\sqrt[3]{xyz}\le\sqrt[3]{\left(a+x\right)\left(b+y\right)\left(c+z\right)}\)
Từ đó suy ra:\(\sqrt[3]{3+\sqrt[3]{3}}+\sqrt[3]{3-\sqrt[3]{3}}\le2\sqrt[3]{3}\)
Cho a, b,c là 3 độ dài 3 cạnh tam giác và
S=\(\sqrt{a^2+b^2}+\sqrt{b^2+c^2}+\sqrt{c^2+a^2}\)
CMR: \(\sqrt{2\left(a+b+c\right)}\le S\le\sqrt{3}\left(a+b+c\right)\)
Bài 1: CMR:
a, (4+\(\sqrt{3}\)). (4-\(\sqrt{3}\))=13
b, \(\sqrt{8+2\sqrt{7}}-\sqrt{8-2\sqrt{7}}=2\)
c, \(\frac{\sqrt{1}}{2+\sqrt{3}}+\frac{\sqrt{1}}{2-\sqrt{3}}=4\)
d, \(\frac{a\sqrt{b}+b\sqrt{a}}{\sqrt{ab}}:\frac{1}{\sqrt{a}-\sqrt{b}}=a-b\)(a>0, b>0, a≠b)
Bài 2: CMR:
a, \(\sqrt{a}+\frac{\sqrt{1}}{\sqrt{a}}\ge2\left(a>0\right)\)
b, a+b+\(\frac{1}{2}\ge\sqrt{a}+\sqrt{b}\left(a,b>0\right)\)
c, \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\ge\frac{1}{\sqrt{xyz}}+\frac{1}{\sqrt{yz}}+\frac{1}{\sqrt{zx}}\left(x,y,z>0\right)\)
d, \(\frac{\sqrt{3}+2}{\sqrt{3}-2}-\frac{\sqrt{3}-2}{\sqrt{3}+2}=-8\sqrt{3}\)
e, \(\frac{a\sqrt{a}+b\sqrt{b}}{\sqrt{ab}}:\frac{1}{\sqrt{a}-\sqrt{b}}\)=a-b(a>0, b>0, a≠b)
Bài 3: Tìm Min hoặc Max(nếu có):
a, \(\sqrt{x^2+9}\)
b, \(\frac{2}{\sqrt{x^2+1}}\)
c, 1-\(\sqrt{5+2x-x^2}\)
