Vì: \(a,b,c>0\)
\(\rightarrow2a+b>0\)
\(2b+c>0\)
\(2c+a>0\)
Áp dụng BĐT SVac-xơ có
\(\frac{1}{2a+b}+\frac{1}{2b+c}+\frac{1}{2c+a}\ge\frac{\left(1+1+1\right)^2}{2a+b+2b+c+2c+a}=\frac{3}{a+b+c}\)
Vì: \(a,b,c>0\)
\(\rightarrow2a+b>0\)
\(2b+c>0\)
\(2c+a>0\)
Áp dụng BĐT SVac-xơ có
\(\frac{1}{2a+b}+\frac{1}{2b+c}+\frac{1}{2c+a}\ge\frac{\left(1+1+1\right)^2}{2a+b+2b+c+2c+a}=\frac{3}{a+b+c}\)
Cho a,b,c >0 . Chứng minh rằng : \(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}+\frac{2a}{b+2a}+\frac{2b}{c+2b}+\frac{2c}{a+2c}\)≥3
Cho a,b,c > 0 . CMR : \(2\left(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}\right)\)≥\(1+\frac{b}{b+2a}+\frac{c}{c+2b}+\frac{a}{a+2c}\)
Cho a,b,c > 0.CMR:
a, \(\frac{1}{a}+\frac{1}{b}\ge\frac{4}{a+b}\)
b, \(2\left(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}\right)\ge1+\frac{b}{b+2a}+\frac{c}{c+2b}+\frac{a}{a+2c}\)
Cho a,b,c>0 , chứng minh rằng:
\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\ge3\left(\frac{1}{a+2b}+\frac{1}{b+2c}+\frac{1}{c+2a}\right)\)
Cho a, b, c > 0. Chứng minh rằng: \(2\left(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}\right)\ge1+\frac{b}{b+2a}+\frac{c}{c+2b}+\frac{a}{a+2c}\)
Cho a,b,c >0
Chứng minh : \(\frac{a}{b+2c}+\frac{b}{c+2a}+\frac{c}{a+2b}\)≥\(1+\frac{b}{b+2a}+\frac{c}{c+2b}+\frac{a}{a+2c}\)
( Nếu có sai đề thì làm ơn sửa lại đề nhé mấy bạn , tks )
cho a,b,c>0; p=a+b+c Chứng minh \(\frac{1}{p-a}+\frac{1}{p-b}+\frac{1}{p-c}\ge2\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)
Cho a,b,c là số thực dương thỏa a+b+c=3 . Chứng minh \(\frac{1}{2 +a^2b}+\frac{1}{2+b^2c}+\frac{1}{2+c^2a}\ge1\)
cho 0<a,b,c<\(\frac{1}{2}\)thỏa mãn a+b+c=1
CMR: \(\frac{1}{a\left(2b+2c-1\right)}+\frac{1}{b\left(2c+2a-1\right)}+\frac{1}{c\left(2a+2b-1\right)}\ge27\)
Cho a,b,c>0 CMR:
\(\frac{1}{2a+b+c}+\frac{1}{a+2b+c}+\frac{1}{a+b+2c}\le\frac{1}{4}\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)