\(3a^2+3b^2=10ab\)
\(\Leftrightarrow3a^2-10ab+3b^2=0\)
\(\Leftrightarrow3a^2-9ab-ab+3b^2=0\)
\(\Leftrightarrow3a\left(a-3b\right)-b\left(a-3b\right)=0\)
\(\Leftrightarrow\left(3a-b\right)\left(a-3b\right)=0\)
=>b=3a hoặc a=3b
TH1: b=3a
\(P=\dfrac{b-a}{b+a}=\dfrac{3a-a}{3a+a}=\dfrac{2a}{4a}=\dfrac{1}{2}\)
TH2: a=3b
\(P=\dfrac{b-3b}{b+3b}=\dfrac{-2b}{4b}=-\dfrac{1}{2}\)