Ta có : a//b
⇒ \(\widehat{N}2=\widehat{M}\) ( 2 góc so le trong )
Mà \(\widehat{M}=55^o\Rightarrow\widehat{N2}=55^o\)
Vậy \(\widehat{N2}=55^{^{ }o}\)
Ta có : \(\widehat{N2}+\widehat{N1}=\widehat{N}\)
\(55^O+\widehat{N1}=90^O\)
\(\widehat{N1}=90^O-55^{^{ }O}\)
\(\widehat{N1}=35^O\)
Vậy \(\widehat{N1}=35^o\)
Ta có : a//b
\(\Rightarrow\widehat{N}=\widehat{C}\) ( 2 góc so le trong )
Mà \(\widehat{N}=90^O\Rightarrow\widehat{C}=90^O\)
Vậy \(\widehat{C}=90^O\)
Có a//b
=> góc N1 + góc CMa = 1800 (2 góc trong cùng phía)
góc N1 = 1800 - góc CMa = 1800 - 550 = 1250
Vì \(a\) // \(b\left(gt\right)\)
=> \(\widehat{N_2}=\widehat{M}\) (vì 2 góc so le trong)
Mà \(\widehat{M}=55^0\left(gt\right)\)
=> \(\widehat{N_2}=55^0.\)
Ta có: \(\widehat{N_1}+\widehat{N_2}=\widehat{N}\)
=> \(\widehat{N_1}+55^0=90^0\)
=> \(\widehat{N_1}=90^0-55^0\)
=> \(\widehat{N_1}=35^0.\)
Vì \(a\) // \(b\left(gt\right)\)
=> \(\widehat{N}=\widehat{C}\) (vì 2 góc so le trong)
Mà \(\widehat{N}=90^0\left(gt\right)\)
=> \(\widehat{C}=90^0.\)
Vậy \(\widehat{N_1}=35^0;\widehat{C}=90^0.\)
Chúc bạn học tốt!
