Mình nghĩ bạn ghi sai đề rồi là \(a^2-3c^2\) mới đúng
Đúng 0
Bình luận (0)
Bài 8: Tính chất của dãy tỉ số bằng nhau
Các câu hỏi tương tự
Cho a/b =c/d
CMR: a^2-3c^2/b^2-3c^2=ac/bd
1)Cho a/a+b=c/c+d
Chứng minh rằng: a/b= c/d
2)cho a/b=c/d, chứng minh rằng
a)3a+2c/3b+2d=-5a+3c/-5b+3d
b)a^2/b^2=2c^2-ac/2d^2-b-d
NHANH NHA! MÌNH ĐANG CẦN GẤP!!!
1. Cho dfrac{a}{b} dfrac{c}{d} c/m
a) (2a+3c) . (2b-3d) (2a- 3c) . (2b+3d)
b) dfrac{left(a^2+cright)^2}{left(b+dright)^2} dfrac{left(a-cright)^2}{left(b-dright)^2}
c)dfrac{a^3+b^3}{c^3+d^3} dfrac{a^3-b^3}{c^3-d^3}
d) dfrac{a^{2018}-b^{2018}}{a^{2018}+b^{2018}} dfrac{c^{2018}-d^{2018}}{c^{2018}+d^{2018}}
HELP ME ~ !!!
Đọc tiếp
1. Cho \(\dfrac{a}{b}\) = \(\dfrac{c}{d}\) c/m
a) (2a+3c) . (2b-3d) = (2a- 3c) . (2b+3d)
b) \(\dfrac{\left(a^2+c\right)^2}{\left(b+d\right)^2}\) = \(\dfrac{\left(a-c\right)^2}{\left(b-d\right)^2}\)
c)\(\dfrac{a^3+b^3}{c^3+d^3}\) = \(\dfrac{a^3-b^3}{c^3-d^3}\)
d) \(\dfrac{a^{2018}-b^{2018}}{a^{2018}+b^{2018}}\) = \(\dfrac{c^{2018}-d^{2018}}{c^{2018}+d^{2018}}\)
HELP ME >~< !!!
Cho TLT a/b=c/d. Chứng minh 3a+4b/5a-3b = 3c+4d/5c-3d bằng 2 cách
Cho a/b = c/d.CMR \(\dfrac{a}{d}\) = \(\dfrac{a^2+b^2}{b^2+d^2}\)
Cho a/b = c/d
a, C/m : \(\frac{a^2+ac}{c^2-ac}=\frac{b^2+bd}{b^2-bd}\)
b, C/m : \(\frac{10a^2+5ab}{16a^2-b^2}=\frac{10c^2+5cd}{16c^2-d^2}\)
1. cho dfrac{a}{b} dfrac{d}{c}
a) dfrac{a+b}{b} dfrac{c+d}{d}
b) dfrac{a}{a-b} dfrac{c}{c-d}
c) dfrac{2a-5b}{2c-5d} dfrac{3a+4b}{3c+4d}
d) dfrac{a^2-c^2}{b^2-d^2} dfrac{ac}{bd}
HELP ME !!! MK SẼ TICK CHO
Đọc tiếp
1. cho \(\dfrac{a}{b}\) = \(\dfrac{d}{c}\)
a) \(\dfrac{a+b}{b}\) = \(\dfrac{c+d}{d}\)
b) \(\dfrac{a}{a-b}\) = \(\dfrac{c}{c-d}\)
c) \(\dfrac{2a-5b}{2c-5d}\) = \(\dfrac{3a+4b}{3c+4d}\)
d) \(\dfrac{a^2-c^2}{b^2-d^2}\) = \(\dfrac{ac}{bd}\)
HELP ME !!! MK SẼ TICK CHO
Cho \(b^2=ac\), \(d^2=bd\)
C/m : \(\frac{a^3+b^3-c^3}{b^3+c^2-d^3}=\left(\frac{a+b+c}{b+c-d}\right)^3\)
\(\dfrac{2a+3c}{2b+3d}=\dfrac{2a-3c}{2b-3d}\)
Chứng minh: \(\dfrac{a}{b}=\dfrac{c}{d}\)