\(\Leftrightarrow ab-4a+3b-12-\left(ab+4a-3b-12\right)=0\)
=>-4a+3b-4a+3b=0
=>-8a=-6b
=>4a=3b
hay a/3=b/4
Ta có :
\(\left(a+3\right)\left(b-4\right)\left(a-3\right)\left(b+4\right)=0\)
\(\Rightarrow ab-4a+3b-12-\left(ab+4a-3b-12\right)=0\)
\(\Rightarrow ab-4a+3b-12-ab+4a+3b+12=0\)
\(\Rightarrow6b-8a=0\)
\(\Rightarrow3b=4a\)
\(\Rightarrow\dfrac{a}{3}=\dfrac{b}{4}\)