Gọi số mol MO là x (mol)
\(n_{H_2SO_4}=0,7.1=0,7\left(mol\right)\)
\(n_{NaOH}=0,4.1=0,4\left(mol\right)\)
PTHH: \(MO+H_2SO_4\rightarrow MSO_4+H_2O\)
________x------->x_______________________(mol)
\(2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O\)
__0,4--------->0,2_________________________(mol)
=> x + 0,2 = 0,7
=> x = 0,5 (mol)
=> \(M_{MO}=\dfrac{20}{0,5}=40\) (g/mol)
=> MM = 24 (g/mol)
=> Mg
CTHH: MgO
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