Question

Cho 2 đa thức j (x) = x5 - x3 - x2 - 2x +5 và g (x) = x2 - 3x + 1 + x2 - x4 + x5.

Hãy tính tổng j (x) + g (x)

Answer 1

\(Tacó:f\left(x\right)+g\left(x\right)=x^5-x^3+x^2-2x+5+x^2-3x+1+x^2-x^4+x^5\)

Answer 2

Ta có : j(x) + g(x) = (x5 - x3 - x2 - 2x +5 )+( x2 - 3x + 1 + x2 - x4 + x5)

= x5 - x3 - x2 - 2x +5+x2 - 3x + 1 + x2 - x4 + x5

=(x5 + x5) + (-3x - 3x) + (-2x+2x-2x)+ (5 +1) -4x

= 10x - 6x - 2x +6 - 4x

= -2x +6

Vậy j(x) + g(x) = -2x +6

Answer 3

\(j\left(x\right)+g\left(x\right)=2x^5-x^4-x^3+x^2-5x+6\)

#Walker

Answer 4

j (x) + g ( x ) = ( x5 - x3 - x2 - 2x + 5 ) + ( x2 - 3x + 1 + x2 - x4 + x5 )

= x5 - x3 - x2 - 2x + 5 + x2 - 3x + 1 + x2 - x4 + x5

= ( x5 + x5 ) + ( - 3x - 3x ) + ( - x2 + x2 + x2 ) + ( 5 + 1 ) + ( - x4 ) + ( -2x )

= x10 - 9x + x2 + 6 - x4 - 2x

Answer 5

mình ko biết đung hay sai nah