\(x^3-6x^2+11x-6=0\\ \Leftrightarrow\left(x^3-x^2\right)-\left(5x^2-5x\right)+\left(6x-6\right)=0\\ \Leftrightarrow x^2\left(x-1\right)-5x\left(x-1\right)+6\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x^2-5x+6\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x-2\right)\left(x-3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\\x=3\end{matrix}\right.\)