Question

Bài 5: So sánh

1,A=\(\sqrt{13}\) + \(\sqrt{20}\)

    B=\(\sqrt{24}\) + \(\sqrt{19}\)

2,A=\(\sqrt{26}\) + \(\sqrt{10}\) 

   B=\(\sqrt{64}\)

Answer 1

Bài 2: 

\(A=\sqrt{26}+\sqrt{10}>\sqrt{25}+\sqrt{9}=5+3=8\)

\(B=\sqrt{64}=8\)

Do đó: A>B

Answer 2

1.Ta có:

\(A=\)\(\sqrt{13}+\sqrt{20}=\sqrt{13}+2\sqrt{5}\)

\(B=\)\(\sqrt{24}+\sqrt{19}=\sqrt{19}+2\sqrt{6}\)

So sánh ta thấy:

\(\sqrt{13}<\sqrt{19}\) ; \(2\sqrt{5}<2\sqrt{6}\)

Vậy A < B