Câu 1:
a: \(\dfrac{x+2}{x-3}-\dfrac{x}{x}=\dfrac{x+9}{x\left(x-3\right)}\)
\(\Leftrightarrow x^2+2x-x^2+3x=x+9\)
=>5x=x+9
=>4x=9
hay x=9/4(nhận)
b: \(\Leftrightarrow\dfrac{x-1}{2}-\dfrac{x-2}{3}=x-\dfrac{x-3}{4}\)
=>6(x-1)-4(x-2)=12x-3(x-3)
=>6x-6-4x+8=12x-3x+9
=>2x+2=9x+9
=>x=-1