\(\frac{4^{20}(2^{20}+1)}{4^{15}(4^{10}+1)}=4^5=1024 \)
Bài 2
Ta có; \((x-2)^{2012}\ge0\)
\(|y^2-9|^{2014}\ge0\)
=>\((x-2)^{2012}+|y^2+9|^{2014}\ge0\)
Mà \((x-2)^{2012}+|y^2+9|^{2014}=0\)
=>x-2=0=>x=2
y^2-9=0=>y=+-3
\(\frac{4^{20}(2^{20}+1)}{4^{15}(4^{10}+1)}=4^5=1024 \)
Bài 2
Ta có; \((x-2)^{2012}\ge0\)
\(|y^2-9|^{2014}\ge0\)
=>\((x-2)^{2012}+|y^2+9|^{2014}\ge0\)
Mà \((x-2)^{2012}+|y^2+9|^{2014}=0\)
=>x-2=0=>x=2
y^2-9=0=>y=+-3
1. Tìm x biết:
a) \(\left(x+36\right)^2=1936\)
b) \(\dfrac{3}{5}^{x+2}=\dfrac{81}{625}\)
c) \(2005^{\left(2x-1\right)\left(2+3x\right)}=1\)
d) \(\left(\dfrac{9}{16}\right)^{x-5}=\left(\dfrac{4}{3}\right)^4\)
e) \(\left(\dfrac{3}{5}\right)^x.\left(\dfrac{125}{72}\right)^5=\dfrac{81}{625}\)
2. a) Tìm x biết:
\(\left(3x+1\right)^4=\left(3x-1\right)^2\)
b) Có số hữu tỉ x thõa mản đẳng thức
\(\left(3x+1\right)^4+\left(3x-1\right)^2=0\)
3. Tính giá trị của biểu thức:
\(A=\left\{-\left[-\left(\dfrac{1}{x}\right)^2\right]^3\right\}^5.\left\{-\left[-\left(-x\right)^5\right]^2\right\}^3\) ( \(x\notin0\)
4. Tìm các cặp số (x,y) thõa mản các đk sau:
a) \(x\left(x+y\right)=\dfrac{5}{12}\) và \(y\left(x+y\right)=\dfrac{5}{18}\)
b) \(x\left(x-y\right)=\dfrac{2}{45}\) và \(y\left(x-y\right)=\dfrac{1}{25}\)
Mai nộp rồi còn 4 bài đó ( help me )
Tìm x, y biết: \(\left(\dfrac{1}{2}\times x-5\right)^{20}+\left(y^2-\dfrac{1}{2}\right)^{20}\le0\)
Bài 1:Tính
a)\(\left(\dfrac{3}{7}+\dfrac{1}{2}\right)^2\) b)\(\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)c) \(\dfrac{5^4.20^4}{25^5.4^5}\)
Bài 2:Tìm x
a)\(\left(x-\dfrac{1}{5}\right)^{2004}+\left(y+0,4\right)^{100}+\left(z-3\right)^{678}=0\)
b)\(\left(x+5\right)^3=-64\) c)\(\left(2x-3\right)^2=9\)
c)\(x^2+1=82\)
Bài 3:Tính
M=\(\dfrac{8^{10}+4^{10}}{8^4+4^{11}}\)
Bài 4:So sánh \(2^{24}\)và\(3^{16}\)
GIÚP MIK DZỚI,MÌNH TIK CHO ><
Tìm x, y biết:
a) \(2^{x+1}.5^y=20^x\)
b) \(\left(2x-1\right)^4+\left(3y-6\right)^2\le0\)
Tìm x, y biết:
a) \(3^x=9^{y-1}\) với \(8^y=2^{x+8}\)
b) \(\left(2x-1\right)^2+\left(4y-1\right)^4=0\)
Bài 27: Tính
a) \(\left(\dfrac{-1}{3}\right)^4\)
b)\(\left(\dfrac{-9}{4}\right)^3\)
c) \(\left(-0,2\right)^2\)
d) \(\left(-5,3\right)^0\)
Bài 1:Tính giá trị biểu thức
\(_{1,}\)\(3^2.\dfrac{1}{243}.81^2.\dfrac{1}{3^3}\)
\(_{2,}\)(\(4.2^5\)):\(\left(2^3.\dfrac{1}{16}\right)\)
\(_{3,}\)\(\left(2^{-1}+3^{-1}\right)+\left(2^{-1}.2^0\right):2^3\)
\(_{4,}\)\(\left(-\dfrac{1}{3}\right)^{-1}-\left(-\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)
\(_{5,}\)[(0,1)\(^2\)]\(^0\)+[(\(\dfrac{1}{7}\))\(^{-1}\)]\(^2\).\(\dfrac{1}{49}.\left[\left(2^2\right)^3:2^5\right]\)
Bài 2:Rút gọn biểu thức
a,\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
b,\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}\)
c,\(\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3\)
\(\overline{2^7.5^2+512}\)
d,\(\left(\dfrac{2}{3}\right)^3.\left(-\dfrac{3}{4}\right)^2.\left(-1\right)^5\)
\(\overline{\left(\dfrac{2}{5}\right)^2}.\left(-\dfrac{5}{12}\right)^3\)
Tính giá trị của biểu thức sau:
B = \(\dfrac{\left(-12\right)^5\times27^4-32^2\times81^4}{729^4\div\left(-9\right)^4\times16^5\div\left(-8\right)^3}\)
4. Tìm x biết:
a) (3x - 7)5 = 0;
b) \(\frac{1}{4}\) - (2x - 1)2 = 0;
c) \(\frac{1}{16}\) - (5 - x)3 = \(\frac{31}{64}\);
d) 2x = (3,8)3 : (-3,8)2;
e) \(\left(\frac{27}{64}\right)^9\). x = \(\left(-\frac{3}{4}\right)^{32}\);
f) \(5^{\left(x+5\right)\left(x^2-4\right)}\) = 1;
g) (x - 2,5)2 = \(\frac{4}{9}\);
h) \(\left(2x+\frac{1}{3}\right)^3=\frac{8}{27}\)