Question

Bài 1: Giải ptrình
a) \(-2\sqrt{2}x-1=2\sqrt{2}x^2+2x+3\)
b) \(x^2-2\sqrt{3}x-\sqrt{3}=2x^2+2x+\sqrt{3}\)
c) \(\sqrt{3}x^2+2\sqrt{5}x-3\sqrt{3}=-x^2-2\sqrt{3}x+2\sqrt{3}+1\)
 

Answer 1

a: =>\(x^2\cdot2\sqrt{2}+x\left(2+2\sqrt{2}\right)+4=0\)

\(\text{Δ}=\left(2\sqrt{2}+2\right)^2-4\cdot2\sqrt{2}\cdot4=12-24\sqrt{2}< 0\)

=>PTVN

b: 

\(\Leftrightarrow2x^2+2x+\sqrt{3}-x^2+2\sqrt{3}x+\sqrt{3}=0\)

=>\(x^2+x\left(2\sqrt{3}+2\right)+2\sqrt{3}=0\)

\(\text{Δ}=\left(2\sqrt{3}+2\right)^2-4\cdot2\sqrt{3}=16>0\)

PT có hai nghiệm là;

\(\left\{{}\begin{matrix}x_1=\dfrac{-2\sqrt{3}-2-4}{2}=-\sqrt{3}-3\\x=\dfrac{-2\sqrt{3}-2+4}{2}=-\sqrt{3}+1\end{matrix}\right.\)