Lời giải:
\((x^3-x^2)-4x^2+8x-4=0\)
\(\Leftrightarrow x^2(x-1)-4(x^2-2x+1)=0\)
\(\Leftrightarrow x^2(x-1)-4(x-1)^2=0\)
\(\Leftrightarrow (x-1)[x^2-4(x-1)]=0\)
\(\Leftrightarrow (x-1)(x^2-4x+4)=0\)
\(\Leftrightarrow (x-1)(x-2)^2=0\)
\(\Rightarrow \left[\begin{matrix} x=1\\ x=2\end{matrix}\right.\)